Sunday, December 23, 2007

Solutions to QA Questions Part1

The solutions to yesterday's QA questions part 1 are given below along with their questions.




  1. Q: A farmer built a fence around his 17 cows,in a square shaped region.He used 27 fence poles on each side of the square. How many poles did he need altogether???

    A: Here 25 poles Must be there on each side .And around four corners 4 poles will be present. 4*25+4=100+4=104 poles.



  2. Q: A group consists of equal number of men and women. Of them 10% of men and 45% of women are unemployed. If a person is randomly selected from the group. Find the probability for the selected person to be an employee.

    A: Assume men=100,women=100 then employed men & women r (100-10)+(100-45)=145
    So probability for the selected person to be an employee=145/200=29/40


  3. Q: A radio when sold at a certain price gives a gain of 20%. What will be the gain percent, if sold for thrice the price?

    A: Let x be original cost of the radio.
    The selling price = (100+20)x=120x
    If , it is sold for thrice the price ,then 3*120x=360x
    So, gain percent is (360-100)=260%.


  4. Q: The diameter of the driving wheel of a bus is 140cm. To achieve the speed of 66 kmph, how many revolutions the wheel must make per minute?

    A: Distance to be covered in 1 min=(66*1000)/60 m=1100m
    Circumference of the wheel =(2*22/7*0.70)m=4.4m.
    So, Number of revolutions per min=1100/4.4=250.


  5. Q: In a college ,1/5 th of the girls and 1/8 th of the boys took part in a social camp.What of the total number of students in the college took part in the camp?

    A: Out of 5 girls 1 took part in the camp
    out of 8 boys 1 took part in the camp
    so, out of 13 students 2 took part in the camp.
    So, 2/13of the total strength took part in the camp.


  6. Q: 5/9 part of the population in a village are males. If 30% of the males are married, what is the percentage of unmarried
    females in the total population?

    A: Let the population =x Males=(5/9)x
    Married males = 30% of (5/9)x = x/6
    Married females = x/6
    Total females = (x-(5/9)x)=4x/9
    Unmarried females = (4x/9 – x/6) = 5x/18
    Required percentage = (5x/18 * 1/x * 100) = (250/9)%


  7. Q: If the first day of 2003 is Sunday what day is the second last day?

    A: As 2003 is not a leap year, it'll consist of 365 days and 364th day'll be Sunday


  8. Q: Walking 5/6 of its usual speed, a train is 10min late. What is the usual time to cover the journey?

    A: New speed = 5/6 of usual speed
    New time = 6/5 of usual time
    Therefore, (6/5 of usual time) – usual time = 10min
    Hence, Usual time = 50min


  9. Q: Two persons A and B working together can dig a trench in 8 hrs while A alone can dig it in 12 hrs. In how many hours B alone can dig such a trench?

    A: (A+B)’s one hour’s work =1/8, A’s one hour’s work =1/12
    Therefore, B’s one hour’s work = (1/8-1/12) =1/24.
    Hence, B alone can dig the trench in 24 hours.


  10. Q: A man buys an article for Rs. 27.50 and sells it for Rs. 28.60. What is his gain percent?

    A: Profit= Rs. 1.1
    Gain percent=(Profit/Cost)*100=4%


  11. Q: The time in a clock is 20 minute past 2. What is the angle between the hands of the clock?


    A: Time is 2:20. Position of the hands: Hour hand at 2 (nearly).
    Minute hand at 4
    Angle between 2 and 4 is 60 degrees [(360/12) * (4-2)]
    Angle made by the hour hand in 20 minutes is 10 degrees, since it turns through ½ degrees in a minute.
    Therefore, angle between the hands is 60 degrees - 10 degrees = 50 degrees


  12. Q: How long will it take for a sum of money to grow from Rs.1250 to Rs.10,000, if it is invested at 12.5% p.a simple interest?

    A: Simple interest is given by the formula SI = (pnr/100), where p is the principal, n is the number of years for which it is
    invested, r is the rate of interest per annum
    In this case, Rs. 1250 has become Rs.10,000.
    Therefore, the interest earned = 10,000 – 1250 = 8750.
    8750 = [(1250*n*12.5)/100]
    => n = 700 / 12.5 = 56 years.


  13. Q: A moves 3 kms east from his starting point. He then travels 5 kms north. From that point he moves 8 kms to the east.How far is A from his starting point?

    A: The total separation in east direction from starting point=8+3=11 kms
    The total separation in north direction from starting point=5 kms
    therefore distance from original point= under-root of 156


  14. Q: In the word ORGANISATION if we exchange first with the second, second with the third, third with fourth and so on.Till last then what will be the 10 letter from right?Explain clearly step by step

    A: Letter A


  15. Q: If log 0.317=0.3332 and log 0.318=0.3364 then find log 0.319.

    A: log 0.319=log 0.318 +(log 0.318-log 0.317)
    log 0.319=0.3396


  16. Q: A work is done by the people in 24 min. One of them can do this work alone in 40 min. How much time required to do the same work for the second person

    A: Similar to ques 9 above. Answer is 60 min.


  17. Q: In a company 30% are supervisors and 40% employees are male if 60% of supervisors are male. What is the probability that a randomly chosen employee is a male or female?


    A: Suppose there are 100 employees in company.
    30 of them are supervisors.
    40 employees out of 100 are male if there are 18 male supervisors.
    The probability of selecting a male employee is 0.4


  18. Q: If TAP is coded as SZO, then how is FREEZE coded?

    A: Each alphabet is converted to its previous alphabet, therefore
    FREEZE 'll be coded as EQDDYD




  19. Q: Kailash faces towards north. Turning to his right, he walks 25 meters. He then turns to his left and walks 30 meters. Next, he moves 25 meters to his right. He then turns to his right again and walks 55 meters. Finally, he turns to the right and moves 40 meters. In direction is he now from his starting point?


    A: in west direction


1 comments:

Anonymous said...

Plz give solns to last questions